Physics, asked by sakshinigam2004, 1 year ago

at what height above the surface of the earth the value of g decreases by 2%​

Answers

Answered by madhavy03
0

Answer:

99/100g = g (1 - 2h/R)

99/100 = 1 - 2h/R

2h/R = 1 - 99/100

2h/R = 1/100

h = R/200

h = 6400/200 (R = 6400KM)

H = 32KM From surface of earth

Explanation:

Answered by Anirudhbhardwaj01
0

We know that gravity at any height is given as;

g’ = g (1 - 2h/R) —[1]

Decrease by 2% implies that g’ = 98/100g

Substitute In 2,we get

.

98/100g = g (1 - 2h/R)

98/100 = 1 - 2h/R

2h/R = 2 - 99/100

2h/R = 1/100

h = R/200

h = 6400/200 (R = 6400KM)

H = 32KM From surface of earth

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