at what height above the surface of the earth the value of g decreases by 2%
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Answer:
99/100g = g (1 - 2h/R)
99/100 = 1 - 2h/R
2h/R = 1 - 99/100
2h/R = 1/100
h = R/200
h = 6400/200 (R = 6400KM)
H = 32KM From surface of earth
Explanation:
Answered by
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We know that gravity at any height is given as;
g’ = g (1 - 2h/R) —[1]
Decrease by 2% implies that g’ = 98/100g
Substitute In 2,we get
.
98/100g = g (1 - 2h/R)
98/100 = 1 - 2h/R
2h/R = 2 - 99/100
2h/R = 1/100
h = R/200
h = 6400/200 (R = 6400KM)
H = 32KM From surface of earth
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