Question

At what height acceleration due to gravity reduce by 25%

Answer 1

At surface of earth
g = GM / R² ……[1]

At height “h”
g’ = GM / (R + h)² ……[2]

Divide equation [1] by equation [2]
g / g‘ = [(R + h) / R]²
g / g’ = (1 + h/R)²
100 / 75 = (1 + h/R)²
10 / sqrt(75) = 1 + h/R
h/R = (10 / sqrt(75)) - 1
h = R × 0.155
h = 992 km

Acceleration due to gravity will reduces to 25% at a height nearly equal to 992 km

Answer 2

Explanation:

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