At what height from the centre of earth the acceleration due to gravity will 1/4th of its value as at the earth.
Answers
Answered by
12
Answer:
Gh=g (r/r+h)^2
Gh/g=(r/r+h)^2
2.45/9.8=(r/r+h)^2
0.25=(r/r+h)^2
0.5=r/r+h
r+h=r/0.5
6.4×10^6+h=6.4×10^6/0.5
6.4×10^6+h=1.28×10^7
h=(1.28×10^7)-(6.4×10^6)
h=6.4×10^6
Means at the height of earth radius g becomes one fourth of its g
Explanation:
Similar questions