At what height from the earth's surface the acceleration due to gravity will be quarter of its value at the surface of earth? (Re = 6400 km)
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4600 km
5000 km
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Answer:
Let the force of gravitational on an object of mass m at an altitude h from earth's surface be equal to F.
Radius of earth =Re=6400km
and mass of earth be Me.
F=G(Re+h)2Mem=mg′
So, g′=(Re+h)2GMe
g=Re2GMe
gg′=(Re+hRe)2=10064
Re+hRe=0.8
So the altitude =h=4Re
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