at what height from the surface of earth the acc. due to gravity is same as the depth of 160km below the surface of earth if the radius of earth is 6400km
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Answered by
34
g_d = g_h
g(1 - d/R) = g(1 - 2h/R)
d = 2h
h = d/2
h = 160 / 2
h = 80 km
Acceleration due to gravity will be same at height nearly equal to 80 km from earth’s surface.
g(1 - d/R) = g(1 - 2h/R)
d = 2h
h = d/2
h = 160 / 2
h = 80 km
Acceleration due to gravity will be same at height nearly equal to 80 km from earth’s surface.
Answered by
18
Radius of earth = 6400 km
We know
g (1 - d/R) = g (1 - 2h/R )
d = 2h
h = d/2
h = 160/2
h = 80 km
By
Sonam Tyagi
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