Physics, asked by pooj7653, 11 months ago

At what height from the surface of earth will the value of g becomes 40% from the value at the surface of earth. Take radius of the earth = 6.4 xx 10^(6) m.

Answers

Answered by tarunbhargaw
3

Answer:

1.92 × 10^6 m

Explanation:

g' = g(1- 2h/R)

g' = g× 40/100 = 0.4 g

so,

0.4 g = g(1- 2h/R)

solving, 2h/R = 0.6

h = 1.92 × 10^6 m

Answered by prachi8707rathore
1
Answer: 12.8*10^6 meter


Explanation:

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