Question

At what height from the surface of Earth will the value of g reduce by 36% from the value at the surface ? Radius of Earth is 6400km

Answer 1

since g is reduced by 36%

g' =0.64g ………(equation1)

**NOTE: IF QUESTION IS GIVEN g IS REDUCED TO 36% THEN USE g’=0.36g AND IF IT’S GIVEN g IS REDUCEDD BY 36% THEN USE g’=0.64g**

g’ = GM/(R+h)^2

GM= gR^2

so g'=gR^2/(R+h)^2 …...(equation2)

by solving the above equations we have

h=R/4

=1600 km.

hope it helps