Question

at what height from the surface of moon the weight of an object drops to its half the weight at surface​

Answer 1

Explanation:

Every object in the universe attracts every other object with a force which is proportional to the product of their masses and inversely proportional to the square of the distance between them. The force is along the line joining the centres of two objects

Answer 2

The height at which the weight of an object drops to its half the weight at surface of the moon is 719.53 km from the surface of the moon.

Explanation:

We know the formula of the gravity of the moon,

   

                                  ⇒ g = $\frac{Gm}{r^{2} }$

Mass of the moon and the gravitational constant are terms that are fixed. So the radius of the moon must be multiplied by the $\sqrt{2}$ to get the solution.

          Radius of the moon = 1737.1 km

                          Distance = $\sqrt{2}$ x 1737.1

                       Height = 2456.63 - 1737.1

                                = 719.53 m