Physics, asked by nandu7002, 1 year ago

At what height from the surface of the earth will the value of g be reduced to 1/4th the value at the surface of earth? Radius of earth is 6400

Answers

Answered by aniscientist2k
0

g=GM/d^2

g'=g*R^2/(R+h)^2

g'/g=R^2/(R+h)^2

1/4=R^2/(R+h)^2

1/2=R/(R+h)

2R=R+h

h=R=6400km


Answered by ashish55587
1
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