Question

AT What height Over the earth pole the free fall accelaration decreases by one percent (assume the radius of earth to be 6400km)​

Answer 1

Answer:

Explanation:

We know that gravity at any height is given as;

g’ = g (1 - 2h/R) —[1]

Decrease by 1% implies that g’ = 99/100g

Substitute In 1,we get

99/100g = g (1 - 2h/R)

99/100 = 1 - 2h/R

2h/R = 1 - 99/100

2h/R = 1/100

h = R/200

h = 6400/200 (R = 6400KM)

H = 32KM From surface of earth