Question

At what height weight of an object is $\frac{9}{25}$ times of weight on the surface of the earth?

Answer 1

Answer:

Since mass of the object remains same

∴ Weight of object will be proportional to

′

g

′

(acceleration due to gravity)

Given

W

planar

W

earth

=

4

9

g

planet

g

earth

Also, g

surface

=

R

2

GM

(M is mass planet, G is universal gravitational constant, R is radius of planet)

∴

4

9

=

GM

planet

R

earth

2

GM

earth

R

planet

2

=

M

planet

M

earth

×

R

earth

2

R

planet

2

=9

R

earth

2

R

planet

2

∴R

planet

=

2

R

earth

=

2

R