at what height will be a man's weight be half his weight on the surface of Earth?
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The problem cannot be solved using the formula g'/g = 1-(2h/Re) as h/Re is not coming out to be very small. One needs to go back to the original derivation where:
g'/g = (Re/Re + h)^2
as g'=g/2
Re + h=√2Re
h={√2–1}Re
Re= 6400 Km
h=2651Km
This gives h around 2651 Km which is a significantly different from 1600 Km. While solving these problems one needs to identify whether approximated formula is applicable or not.
Hope this helps!!
g'/g = (Re/Re + h)^2
as g'=g/2
Re + h=√2Re
h={√2–1}Re
Re= 6400 Km
h=2651Km
This gives h around 2651 Km which is a significantly different from 1600 Km. While solving these problems one needs to identify whether approximated formula is applicable or not.
Hope this helps!!
rajat8458:
hello bhai main akash hu
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