Question

@ what is the pressure in atm of a 0. 108 mol sample.
of the gas at a temperature of 20.0 degree celsius If its volume is
0.0505l​

Answer 1

Answer:

P = 50.12 atm

Explanation:

P = nRT /V

P = 0.108 * 0.082 * 293 / 0.505

P = 50.12 atm