Question

At what minimum atomic number, a transition from n = 2 to n = 1 energy level results in the emission of X-rays with wavelength 3.0 x 10-8 m?
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Answer 1

Answer:

Explanation:

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Answer 2

Answer:

ANSWER

E

1

for H=−13.6eV

∴E

2

for H=−(−13.6/2

2

)=−13.6/4=−3.4eV

∴E

2

−E

1

=−3.4−(−13.6)=+10.2eV

Also for transition of H like atom; λ=3.0×10

−8

m

λ

1

=R

H

Z

2

[

1

2

1

−

2

2

1

]

3×10

−8

1

=1.09×10

7

×Z

2

×

4

3

∴Z

2

=4 and Z=2

Thus, the H like an atom is He

+

.

Hence, the correct option is A