At what point does the graph of linear equation 3x - 4y = 45 cuts the x axis
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Given linear equation is 3x - 4y = 45
Also given that the graph of the linear equation cute x-axis,So its y-axis must be zero.
We know that the Co-ordinate has two poitns represented as (x,y).
As Y coordinate is zero, so we only have to find X coordinate.
For this, put y = 0 in above equation.
3x - 4 (0) = 45
3x = 45
x = 45/3
x = 15
Hence the point where graph of the given linear equation cuts x-axis is
(x,y) = (15,0)
Also given that the graph of the linear equation cute x-axis,So its y-axis must be zero.
We know that the Co-ordinate has two poitns represented as (x,y).
As Y coordinate is zero, so we only have to find X coordinate.
For this, put y = 0 in above equation.
3x - 4 (0) = 45
3x = 45
x = 45/3
x = 15
Hence the point where graph of the given linear equation cuts x-axis is
(x,y) = (15,0)
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