Question

At what point does the graph of the linear equation x +y =5 meet a line which is parallel to Y axis at a distance of 2 units from the origin and in the negative direction of X axis?

Answer 1

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The required point is (2,3).

Step-by-step explanation:

Given : The graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance of 2 units from the origin in the positive direction of x-axis ?

To find : At what point does the graph meet a line?

Solution :

The graph of the linear equation  .....(1)

The x-intercept is at y=0,

x+0=5

x=5

The y-intercept is at x=0,

0+y=5

y=5

Now, any line parallel to the y axis is in the form x=k.

Since, this line is at a distance of 2 units from the origin in the positive x-axis.

So, The equation of line is  ......(2)

Now, The intersection point of both the lines is the required point.

Put equation (2) in (1),

2+y=5

y=3

Therefore, The required point is (2,3).

Answer 2

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