Question

at what point does the graph of the linear equation x-y=5 cuts the x axis

Answer 1

Understanding plus Solution

Its very simple to say.

y will be equal to zero where the linear equation cuts the x-axis.

hence,

simply put y = 0

$\sf \: x - y = 5 \\ \\ \sf \implies \: x - 0 = 5 \\ \\ \bf \therefore \: x = 5 \\ \\ \odot \: \: \bf\green{pt} : \rightarrow (5,0)$

Answer 2

Answer:

if for an A.P., S15=147 and S14=123, find t15 what is the answer