Question

At what point does the graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distnace of 2 units from the origin in the positive direction of x-axis,

Answer 1

it will be (2,3) in first quadrant

Answer 2

Answer:

The required point is (2,3).

Step-by-step explanation:

Given : The graph of the linear equation x + y = 5 meet a line which is parallel to the y-axis, at a distance of 2 units from the origin in the positive direction of x-axis ?

To find : At what point does the graph meet a line?

Solution :

The graph of the linear equation $x+y=5$ .....(1)

The x-intercept is at y=0,

$x+0=5$

$x=5$

The y-intercept is at x=0,

$0+y=5$

$y=5$

Now, any line parallel to the y axis is in the form x=k.

Since, this line is at a distance of 2 units from the origin in the positive x-axis.

So, The equation of line is $x=2$ ......(2)

Now, The intersection point of both the lines is the required point.

Put equation (2) in (1),

$2+y=5$

$y=3$

Refer the attached figure below.

Therefore, The required point is (2,3).