Question

At what point on the projectile trajectory is the kinetic energy minimum?​

Answer 1

The point on the projectile trajectory where kinetic energy is minimum is at the maximum height  

Detailed answer

This is because the vertical velocity at the maximum height is zero so the kinetic energy is minimum

• ux=vocosθ -  Horizontal component of velocity.

• uy=vosinθ−gt - vertical component of velocity

We know that 'G' is the acceleration due to gravity

We also know that the horizontal component remains constant throughout the time but the vertical velocity decreases with respect to the time and at the highest point or inclination it becomes zero.

Equation

Minimum kinetic energy $= 1/2m(v0cosθ)^2$

$u= vocosθ .$

so it is minimum at the highest point