Question

At what point straight line y=(x/2+1/2) cuts y-axis

Answer 1

The point where the straight line cuts the y-axis is (0,$\frac{1}{2}$)

Therefore the point is (0,$\frac{1}{2}$)

Step-by-step explanation:

• Given straight line is $y=(\frac{x}{2}+\frac{1}{2})$
• To find the point where the straight line cuts the y-axis : If a straight line cuts the y-axis means that the value of x must be equal to zero , that is x-axis is parallel to y-axis
• Therefore put x=0 in the given straight line we get
• $y=(\frac{x}{2}+\frac{1}{2})$
• $y=(\frac{0}{2}+\frac{1}{2})$
• $y=0+\frac{1}{2}$
• $y=\frac{1}{2}$
• From this we get x=0 and $y=\frac{1}{2}$
• Therefore the point is (0,$\frac{1}{2}$)
• The point where the straight line cuts the y-axis is (0,$\frac{1}{2}$)