Question

At what point the graph of the linear equation -2x + y = 10 cuts the y axis?

Answer 1

Answer

To cut the x-axis, y coordinate has to be zero

To cut the x-axis, y coordinate has to be zero-x + 0 = -10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)To cut the y-axis, x coordinate has to be zero

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)To cut the y-axis, x coordinate has to be zero0 + y = -10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)To cut the y-axis, x coordinate has to be zero0 + y = -10y = -10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)To cut the y-axis, x coordinate has to be zero0 + y = -10y = -10y = -10

To cut the x-axis, y coordinate has to be zero-x + 0 = -10-x = -10x = 10So the point of intersection at the x-axis will be (10,0)To cut the y-axis, x coordinate has to be zero0 + y = -10y = -10y = -10So the point of intersection at the y axis will be (0,-10)

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