Question

at what point the graph of the linear equation 3x+5y=15 cuts the x axis and y axis

Answer 1

For ans see attachement

Answer 2

Given,

Linear equation 3x + 5y = 15.

To find,

Points where the line cuts x- and y- axes.

Solution,

We can solve this problem simply by following the process given below.

Here, the equation for a line is given, that is

3x + 5y = 15.

It can be determined at what point this line intersects the x-axis by substituting y = 0 in the equation of the line. That is,

3x + 5·(0) = 15

⇒ 3x = 15

⇒ $x = \frac{15}{3}$

⇒ x = 5

Thus, coordinates of this point = (5, 0).

Now, to find the point where this line cuts the y-axis, put x = 0. So,

3·(0) + 5y = 15

⇒ 5y = 15

⇒ $y= \frac{15}{5}$

⇒ y = 3.

∴ Coordinates of this point = (0, 3).

Therefore, the points of intersection of the given line where it cuts the x- and y- axes will respectively be (5, 0) and (0, 3).