At what points does the line 3x+4y = 6 cuts the x-axis and y-axis.
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Answered by
88
⭐To cut at x axis,
the value of y must be 0
so, putting y=0 in equation
3x+4y=6
3x+4×0=6
3x+0=6
3x=6
x=2
so, the line of equation will cut the x-axis at point (2,0)
⭐To cut at y axis,
the value of x must be 0
so, putting x=0 in the equation
3x+4y=6
3×0+4y=6
0+4y=6
4y=6
y=6/4
y=3/2
So,the line of equation will cut y axis at point (0,3/2)
@Altaf
the value of y must be 0
so, putting y=0 in equation
3x+4y=6
3x+4×0=6
3x+0=6
3x=6
x=2
so, the line of equation will cut the x-axis at point (2,0)
⭐To cut at y axis,
the value of x must be 0
so, putting x=0 in the equation
3x+4y=6
3×0+4y=6
0+4y=6
4y=6
y=6/4
y=3/2
So,the line of equation will cut y axis at point (0,3/2)
@Altaf
ALTAF11:
thanks for brainliest:)
Answered by
6
Answer:
Step-by-step explanation:
To cut at x axis,
the value of y must be 0
so, putting y=0 in equation
3x+4y=6
3x+4×0=6
3x+0=6
3x=6
x=2
so, the line of equation will cut the x-axis at point (2,0)
⭐To cut at y axis,
the value of x must be 0
so, putting x=0 in the equation
3x+4y=6
3×0+4y=6
0+4y=6
4y=6
y=6/4
y=3/2
So,the line of equation will cut y axis at point (0,3/2)
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