Question

at what rate of compound interest of rupees 10000 amounts to rs 11664 in two years.​

Answer 1

AnswEr :

• Principal = Rs. 10,000
• Amount = Rs. 11,664
• Time = 2 Years
• Rate = ?

$\leadsto \sf{Amount = P \times \bigg(1 + \dfrac{r}{100} \bigg)^{t} }$

$\leadsto \sf{11664 = 10000 \times \bigg(1 + \dfrac{r}{100} \bigg)^{2} }$

$\leadsto \sf{ \dfrac{11664}{10000} = \bigg(1 + \dfrac{r}{100} \bigg)^{2} }$

$\leadsto \sf{ \sqrt{\dfrac{11664}{10000}}= 1 + \dfrac{r}{100} }$

$\leadsto \sf{ \sqrt{\dfrac{108 \times 108}{100 \times 100}}= 1 + \dfrac{r}{100} }$

$\leadsto \sf{ \dfrac{108}{100}= 1 + \dfrac{r}{100} }$

$\leadsto \sf{ \dfrac{108}{100} - 1= \dfrac{r}{100} }$

$\leadsto \sf{ \dfrac{8}{\cancel{100}}= \dfrac{r}{\cancel{100}} }$

$\leadsto \boxed{\sf{r = 8\%}}$

⠀

$\therefore$ At rate 8% p.a. Rs.10,000 will turn Rs.11,664 in 2 Years compounded yearly.

Answer 2

Answer:

8 % is the rate of compound interest of rupees 10000 amounts to rs 11664 in two years.

Step-by-step explanation:

Given,

P =rs 10,000

A = rs 11664

t = 2 years

Here,

A is amount

P is principal

r is rate per annum

t is time

Hence

8 % is the rate of compound interest of rupees 10000 amounts to rs 11664 in two years.

PRINCIPLE

The original amount of a debt on which interest is calculated.

RATE

The amount of a money which include principal and interest both.