Question

At what rate of compound interest will ₹ 25000 became ₹36000 in two years

Answer 1

Answer:

20%

Step-by-step explanation:

$formula \: p {(1 + \frac{r}{100}) }^{2} = amount \\ or \: \: 25000 {( \frac{100 + r}{100} )}^{2} = 36000 \\ or \: \: {(100 + r)}^{2} = \frac{36000}{25000} \times 10000 \\ or \: \: 100 + r = \frac{6}{5} \times 100 = 120 \\ or \: \: r = 20$