Question

At what rate of compounds interest will ₹1250 amount to ₹1800 in 2 years

Answer 1

Answer:

20%

Step-by-step explanation:

$\textbf{\underline{\underline{Given\:In\:Question :}}}$

$\sf \: Principal = Rs 1250$

$\sf \: Amount = Rs 1800$

$\sf \: Time = 2 years$

Applying Formula For Compound Interest :

$\sf \: Amount = P (1 + \dfrac{r}{100} ) ^{n}$

Putting Values:

$\sf \: 1800 = 1250(1 + \dfrac{r}{100} ) ^{2}$

$\sf \: \cancel \dfrac{1800}{1250} (1 + \dfrac{r}{100}) ^{2}$

$\sf \: \dfrac{36}{25} = (1 + \dfrac{r}{100} ) ^{2}$

$\sf \: ( \dfrac{6}{5} ) ^{ \cancel2} = (1 + \dfrac{r}{100} ) ^{ \cancel2}$

$\sf \: 1 + \dfrac{r}{100} = \dfrac{6}{5}$

$\sf \: \dfrac{r}{100} = \dfrac{6}{5} - 1$

$\sf \: \dfrac{r}{100} = \dfrac{6 - 5}{5}$

$\sf \: \dfrac{r}{100} = \dfrac{1}{5}$

$\sf \: 5r = 100$

$\sf \: r = \dfrac{100}{5}$

$\huge{\boxed{\rt{20\: \%}}}$