Question

at what rate of interest per annum the simple interest of rupee 300 becomes rupees 45 in 3 years

Answer 1

hiii meta


ur answer


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Let the sum borrowed be Z. Then, (Zx6x2⁄100) + (Zx9x3⁄100) + (Zx14x4⁄100) = 11400 Therefore, 3Z⁄25 + 27Z⁄100 + 14Z⁄25) = 11400 ? 95Z⁄100 = 11400 Z = (11400x100⁄95) = 12000

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$plxx \: hope \: you$


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Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!}}}$
P = 300
T = 3 years
SI = 45
R = ? let r
AS we know the formula
SI = PRT/100
R = SI x 100/PT
$r = \frac{45 \times 100}{300 \times 3} \\ r = \frac{45}{9} \\ r = 5\%$
So The rate of interest= 5%

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