Question

at what rate of interest per annum will ₹800 amount to ₹882 in year when compounded half- yearly?​

Answer 1

Step-by-step explanation:

882=800(1+2×100R)(2×1)

\mapsto\tt{\cancel{\dfrac{882}{800}} =\bigg(1+\dfrac{R}{2\times 100} \bigg)^{2}}↦800882=(1+2×100R)2

\mapsto\tt{\dfrac{441}{400}= \bigg(1+\dfrac{R}{ 200} \bigg)^{2}}↦400441=(1+200R)2

\mapsto\tt{\sqrt{\dfrac{441}{400} } = 1+\dfrac{R}{ 200} }↦400441=1+200R

\mapsto\tt{\dfrac{21}{20}= 1+\dfrac{R}{ 200}}↦2021=1+200R

\mapsto\tt{\dfrac{21}{20}-1= \dfrac{R}{ 200}}↦2021−1=200R

\mapsto\tt{\dfrac{21-20}{20}= \dfrac{R}{ 200}}↦2021−20=200R