At what rate % p.a. will a sum of ₹4000 yield ₹1324 as compound interest in 3 years?
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Given,
P=4000, I=1324, t=3 years,
I=P[(1+R%)^t−1]
1324=4000[(1+R%)^3–1]
1324/4000=(1+R%)^3–1
1324/4000+1=(1+R%)^3
5324/4000=(1+R%)^3
1.331=(1+R%)^3
(1.331)^1/3=1+R%
1.1=1+R%
R%=0.1
R%=10%
❣Hope this helps you mate✌
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