Question

at what rate pcpa will Rupees 1500 amount to rupees 1860 in a period of 3 years​

Answer 1

$\huge\underline\mathtt \orange{Solution:- }$

$\sf{Given}\begin{cases}\sf{principal=1500} \\ \sf{time=3year} \\\sf{rate \:of \:interest =?}\end{cases}$

$\large\underline\textsf{ To Find}$

$\small\textsf{ Rate\: of \:interest =?}$

$\huge\underline\textsf{Explantion:- }$

$\leadsto\bf s.i = a - p$

$\leadsto\bf rs(1860 - 1500)$

$\leadsto\bf 360$

$\small\underline\textsf{ formula Used }$

$\boxed{\bf s.i = \frac{p \times r \times n}{100}}$

$\huge\underline\textsf{ A. T. Q}$

$\leadsto\bf s.i = \frac{p \times r \times n}{100}$

$\leadsto\bf360 = \frac{15\cancel0\cancel0 \times r \times 3}{1\cancel0\cancel0}$

$\leadsto\bf 360 = 15 \times r \times 3 \\ \leadsto\bf360 = 45 \times r$

$\leadsto\bf r = \frac{\cancel3\cancel6\cancel0}{\cancel4\cancel5}$

$\small\underline\textsf{Rate of interest = 8}$

$\huge\underline\textsf{Verification }$

$\sf{Given}\begin{cases}\sf{principal=1500} \\ \sf{time=3year} \\\sf{Rate \:of \:interest =8}\\\sf{Amount=?}\end{cases}$

$\leadsto\bf simple \: interest = \frac{p \times r \times n}{100}$

$\leadsto\bf \frac{1500 \times 8 \times 3}{100}$

$\leadsto\bf 15 \times 8 \times 3 \\ \leadsto\bf360$

$\leadsto\bf s.i = 360$

$\boxed{\bf amount \: formula = p + s.i}$

$\leadsto\bf(1500 + 360) \\ \leadsto\bf1860$

$\huge\underline\textsf{ Hence\: Verified }$