at what rate percent p.a. will a sum of rupees 4000 rupees 1324 as compound interest in 3 years
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Step-by-step explanation:
A= P(1+r/n)nt
we know Anibal amount A= 4000
rate of interest is 1323
time is 3 y
substitute the value in formula
4000=p(1+1324/3) *3
4000=(1+441.33)*3
4000= (442.33)*3
4000 =p(1326.99)
4000/1326.99=p
p= 3.01
Initially principal balance is 3.01
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