Question

At what rate percent per annum will a sum of Rs. 3600 become Rs.4500 in 10 years at simple interest.​

Answer 1

➤ Given :-

Principle (P) :- ₹ 3600

Total amount :- ₹ 4500

Time (T) :- 10 years

➤ To Find :-

Rate of interest for the given sum............

➤ Formula :-

$\bf \large \orange{ \bigstar \: {\underline {\underline {SI \times 100 \div P \times T}}}}$

➤ Solution :-

Simple Interest (SI) :-

$\dashrightarrow \sf4500 - 3600$

$\dashrightarrow \sf900$

Rate of interest (R) :-

$\dashrightarrow \sf \frac{900 \times 100}{3600 \times 10}$

$\dashrightarrow \sf \frac{ \cancel{900} \times 100}{ \cancel{3600} \times 10} = \frac{9 \times 100}{36 \times 10}$

$\dashrightarrow \sf \frac{900}{360} = 2.5 \bf\%$

$\Huge\therefore$The rate of interest is 2.5 $\bf \%$

Answer 2

Step-by-step explanation:

➤ Given :-

Principle (P) :- ₹ 3600

Total amount :- ₹ 4500

Time (T) :- 10 years

➤ To Find :-

Rate of interest for the given sum............

➤ Formula :-

$\bf \large \orange{ \bigstar \: {\underline {\underline {SI \times 100 \div P \times T}}}}$

➤ Solution :-

Simple Interest (SI) :-

4500 - 3600⇢4500−3600

900⇢900

Rate of interest (R) :-

$\begin{gathered} \dashrightarrow \sf \frac{900 \times 100}{3600 \times 10} \\ \end{gathered} </p><p>$

$\begin{gathered} \dashrightarrow \sf \frac{ \cancel{900} \times 100}{ \cancel{3600} \times 10} = \frac{9 \times 100}{36 \times 10} \\ \end{gathered}$

$\begin{gathered} \dashrightarrow \sf \frac{900}{360} = 2.5 \bf\% \\ \end{gathered}$

therefore∴ The rate of interest is 2.5 %