Question

at what rate percentage p.a will rs. 5625 amount to rs. 6084 ib 2 years at compound interest.


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Answer 1

Answer:

Step-by-step explanation:Given : P= Rs12,000; n=3years and r=5%

Amount= =

=

=Rs13,891.50 Ans.

C.I. =RS13,891.50 - Rs12,000

= Rs1,891.50 Ans.

Answer 2

Answer:

4%

Explanation:

We are given that

Principle value =Rs 5625

Amount=Rs 6084

Time=2 years

We have to find the rate of interest.

We know that

$A=P(1+\frac{r}{100})^n$

Where r=Rate of interest

A=Amount

P=Principle

n=Time

Substitute the values then we get

$6084=5625(1+\frac{r}{100})^2$

$\frac{6084}{5625}=(1+\frac{r}{100})^2$

$(\frac{78}{75})^2=(1+\frac{r}{100})^2$

When power same on both sides of equality then base will be equal.

$1+\frac{r}{100}=\frac{78}{75}$

$\frac{r}{100}=\frac{78}{75}-1$

$\frac{r}{100}=\frac{78-75}{75}=\frac{3}{75}$

$r=\frac{3}{75}\times 100=4$%

Hence , rate of interest=4% p.a