At what rate will 1000 amount to 1,331 in 3 years if compounded annually?
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Answer:
P=1000
N=3years
A=1331
We know that A = P(1+r/100)^n
1331 = 1000(1+r/100)^n
1331/1000 = (1+r/100)^3
(11/10)^3= (1+r/100)^3
(11/10)=(1+r/100)
11/10-1=r/100
11-10/10=r/100
1/10=r/100
1 = r/100
r = 10
So,Rate of interest=10%
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