Question

At what rate will a body accelerate when a resultant force of 5400 N is acting?
(mass of the body is 250 kg)
21

12

31

32

Answer 1

Answer:

Here is your answer

Explanation:

Given

Mass of the Object = 250 kg

Force = 5400 Newton

Accelaration = ?

Solution

Using the Rate of Change of Momentum

Force = Mass x Accelaration

Accelaration = Force/Mass

Accelaration = 5400 Newton/250 kg

Accelaration = 21.6 m/s^2

Answer 2

Provided that:

• Force = 5400 Newton
• Mass = 250 kg

To calculate:

• Acceleration

Solution:

• Acceleration = 21 mps sq.

Using concept:

• Second law of motion that tell us about the formula to calculate the force.

Using formula:

• F = ma

Where, a denotes acceleration, F denotes force and m denotes mass.

Required solution:

»»» Force = Mass × Acceleration

»»» F = m × a

»»» F = ma

»»» 5400 = 250(a)

»»» 5400/250 = a

»»» 540/25 = a

»»» 108/5 = a

»»» 21.6 = a

»»» a = 21.6 mps sq.

»»» Acceleration = 21.6 mps sq.

• Henceforth, according to the options at 21 mps sq. will the body accelerated. Therefore, option (a) is correct. $\:$

Additional information:

$\begin{gathered}\boxed{\begin{array}{c}\\ \bf What \: is \: acceleration? \\ \\ \sf The \: rate \: of \: change \: of \: velocity \: of \: an \\ \sf object \: with \: respect \: to \: time \\ \sf is \: known \: as \: acceleration. \\ \\ \sf \star \: Negative \: acceleration is \: known \: as \: deceleration. \\ \sf \star \: Deceleration \: is \: known \: as \: retardation. \\ \sf \star \: It's \: SI \: unit \: is \: ms^{-2} \: or \: m/s^2 \\ \sf \star \: It \: may \: be \: \pm ve \: or \: 0 \: too \\ \sf \star \: It \: is \: a \: vector \: quantity \\ \\ \bf Conditions \: of \pm ve \: or \: 0 \: acceleration \\ \\ \sf \odot \: Positive \: acceleration: \: \sf When \: \bf{u} \: \sf is \: lower \: than \: \bf{v} \\ \sf \odot \: Negative \: acceleration: \: \sf When \: \bf{v} \: \sf is \: lower \: than \: \bf{u} \\ \sf \odot \: Zero \: acceleration: \: \sf When \: \bf{v} \: \sf and \: \bf{u} \: \sf are \: equal \end{array}}\end{gathered}$