Question

At what separation should two equal charges, 1.0c each be placed so that the force between them equals the weight of a 50kg person?

Answer 1

Answer:

4242.6m

Explanation:

F=mg=50kg×10m/s^2=500N

F=Kq^2/r^2

r^2=9×10^9×1×1/500

r^2=4242.6

or

4.2426×10^3

Answer 2

Step-by-step explanation :

Here in this question both the charges are equal (q1 = q2) that is of 1C and the mass of person is 50 kg.

So the electrostatic force would be equal to the force exerted by the person on earth. As we all know that gravitational force is only the force exerted by us on earth.

After substituting the values we would get the value of "r".

Therefore, both the forces would be kept equal.

• Electrostatic force = Gravitational force

As we know that electrostatic force is given by the formula :

• F = k q1 . q2 / r²

(Remember that value of k is always 9 × 10^9

And gravitational force is given by the formula :

• F = mg

Here,

• m is mass

Now,

>> K q1 q2 / r² = mg

>> (9 × 10^9 × 1 × 1 ) / r² = 50 × 9.8

>> (9 × 10^9) / r² = 490

>> r² = 9 × 10^9 / 490

>> r = 4.2 × 10³ m

Therefore, seperation between them is of 4.2 × 10³ m.