Question

at what speed the momentum and kinetic energy of a body having the same value​

Answer 1

EXPLANATION :

$\sf \: Kinetic \: energy \: of \: a \: moving \: body \: \frac{1}{2} m {v}^{2}$

$\sf \: E_k = \frac{1}{2} m {v}^{2}$

$\sf \longrightarrow \: m \: E_k = \frac{1}{2} {(mv)}^{2}$

$\sf \longrightarrow E_k = \frac{ {p}^{2} }{2m}\:$

Form this eqn we can say kinetic energy is constant when ∆v is 0.

That means when ∆p is unchanged