Question

At what speed would the mass of of a proton be doubled?

Answer 1

Answer:

Mass will get doubled, when it will travel at the velocity of c × root1/2, where c is the velocity of light in vacuum.

Explanation:

We will use this formula.

New Mass = Original Mass/[root(1 - v^2/c^2)]

Here, New Mass = 2m & Mass = m

So,

2m = m/[root(1 - v^2/c^2)]

1/[root(1 - v^2/c^2)] = 2

1/(1 - v^2/c^2) = 2

2(1 - v^2/c^2) = 1

1 - v^2 / c^2 = 1/2

- v^2/c^2 = -1/2

v^2/c^2 = 1/2

v^2 = c^2/2

v = c × root1/2

Mass will get doubled, when it will travel at the velocity of c × root1/2, where c is the velocity of light in vacuum.

Answer 2

Answer:

v=√3÷2 C

Explanation:

because m=2mo and where the mass variation s m=mo÷√1_v²÷c² and after solve we get