At what temp, at const pressure volume of ideal gas at 0℃ becomes triple
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apply gay lussac law,
V1T1=V2T2
let V1=x then V2=3x T1=273K
therefore T2= x*273/3x=91 K
T2=182 degree c
V1T1=V2T2
let V1=x then V2=3x T1=273K
therefore T2= x*273/3x=91 K
T2=182 degree c
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