Question

at what temperature 3 moles of so2 will occupy 10 litre and 15 atm pressure
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Answer 1

a and b constant for $SO_2$ is :

$a=6.71\ atm\ liter^2\ mol^{-2}\\\\b=0.0564\ liter \ mol^{-1}$

We know, for real gas :

$(P+\dfrac{an^2}{V^2})(V-nb)=nRT$

Putting all given values in above equation we get :

$(15+\dfrac{6.71\times 3^2}{10^2})(10-3\times 0.0564)=3\times 0.082\times T\\\\T=\dfrac{(15+\dfrac{6.71\times 3^2}{10^2})(10-3\times 0.0564)}{3\times 0.082}\\\\T=623.57\ K$

Hence, this is the required solution.