At what temperature Fahrenheit is double to celcius
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TC/5 = (tf-32)/9
Tc/5 = tf/9 - 32/9
In question
9(Tc/5 + 32/9)= 2Tc
9tc/5 +32 = 2tc
32= 2tc - 9/5 tc
Tc/5 = 32
Tc = 160 degree
TF = 320 farenheit
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