At what temperature is the velocity of sound of air 1.2 times it value at ntp
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At 110.5°C the speed of sound in air will be 1.2 times its value at NTP
Speed of sound at a temperature T is given by,
V = 331.5 + 0.6T
where 331.5 m/s is the velocity of sound at NTP
1.2 times the value of 331.5 will be (1.2 x 331.5) = 397.8
Putting these values in the equation
397.8 = 331.5 + 0.6T
=> 0.6T = 66.3
=> T = 66.3/0.6 = 110.5 °C
Hence at 110.5°C the speed of sound in air will be 1.2 times its value at NTP.
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