Question

At what temperature the average speed of helium molecule will be the same as that of oxygen molecule at 527°C
(a) 100 K
(b) 200 K
(c) 273 K
(d) 400 K

Answer 1

Answer:100k

Explanation:

Answer 2

(b). The temperature the average speed of helium molecule will be the same as that of oxygen molecule at 527°C is 200K

Given:

$M_{1}$ = 16 (Oxygen)

$M_{2} =$ 4 (Helium)

$T_{1} = 527^{0}$ = 800K (Oxygen)

To find:

Temperature of Helium.

Solution:

Formula:

Average speed = $\sqrt{\frac{8RT}{\pi M_{0} } }$.

$M$ is directly proportional to $T$

Hence, $\frac{M_{1} }{T_{1} } = \frac{M_{2} }{T_{2} }$

$\frac{16}{800} = \frac{4}{T_{2} } \\\\T_{2} = \frac{(4)(800)}{16}\\ \\T_{2} = 200K$

Therefore, the temperature the average speed of helium molecule will be the same as that of oxygen molecule at 527°C is 200K