Question

at what temperature, the rate of effusion of N2 would be 1.625 times than that the rate of SO2at 500degree celcious ​

Answer 1

Answer:

R1 = 1.625 R2  and T2 = 500°C = 773 K

-> We know that, R1/R2= √M1 / M2X T1 / T2

= T1 = (1.625)2 X 28 X 773/3

= 893 K = 620 Degrees

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