Question

at what temperature the reading on kelvin scale is 3 times that on celcius scale

Answer 1

we know,
( K -273)/100 = ( C -0)/100

according to question ,
K = 3C

so,

(3C -273)/100 = C/100

3C -273 = C

2C = 273

C = 136.5°C

Answer 2

Answer:  409.5 K

Explanation:

• To convert an temperature from celcius  scale to kelvin scale we add 273 to the celcius scale.
• Let the temperature on kelvin scale be t K.
• In celsius scale the temperature will be (t-273)° C
• According to question,

       t = 3(t-273)

   ⇒ t = 3t - 819

   ⇒ 3t-t = 819

   ⇒ 2t = 819

   ⇒ t = $\frac{819}{2}$

    ∴ t = 409.5 K

• Hence, the required temperature is  409.5 K.

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