Question

At what temperature, the rms velocity of gas shown at 50 ° C will be doubled:​

Answer 1

Concept Introduction: Velocity of gases are the basic concept of Chemistry and Physics.

Given:

We have been Given: Temperature is given as

$50°C = 50 + 273 = 323K$

To Find:

We have to Find: At what temperature, the rms velocity of gas shown at 50 ° C will be doubled?

Solution:

According to the problem, RMS velocity is given as

$v_{rms} = \sqrt{ \frac{3RT}{M} }$

therefore, at

$323K$

RMS Velocity is

$2 v_{rms} = \sqrt{ \frac{3R \times 323}{M} }$

On, dividing the equations we get,

$\frac{1}{4} = \frac{323}{T} \\ T = 4 \times 323 = 1292K$

Final Answer: The temperature is

$1292K \: or \: 1019°C$

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