at what temperature The RMS velocity of gas shown at 50 degree Celsius will be doubled
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T = A V^2
for t = 0o C = 273 o K
T1 = AV1Г2 = 4 A V^2
=-> T1 = T 4 V^2/ V^2 = 273 x 4 x = 1092 oK
=> t1 = 1092 - 273 = 819 oC
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for t = 0o C = 273 o K
T1 = AV1Г2 = 4 A V^2
=-> T1 = T 4 V^2/ V^2 = 273 x 4 x = 1092 oK
=> t1 = 1092 - 273 = 819 oC
Mark me as a Brainliest.
mds30:
ans. is 1019 degree Celsius
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