Question

At what temperature the root mean square velocity of chlorine gas will be equal to so2 at STP

Answer 1

Explanation:

use r=0.0821 and t should be absolute temp NTP is same as stp standard temperature pressure which is 27°c and 1 atm

Answer 2

Given,

Two gases - Chlorine gas and $SO_{2}$ gas.

To Find,

The temperature when the root mean square velocity of chlorine gas will be equal to $SO_{2}$ at STP.

Solution,

We can solve this numerical problem with the following method.

We know that the root mean square velocity or RMS velocity of any gas is,$u_{RMS} = \sqrt{\frac{3RT}{M}$.

We also know the

• molar mass of $SO_{2}$  is 64 g/mol.
• molar mass of chlorine gas is 71g/mol.
• STP = 273k.

At STP root mean square velocity of $SO_{2}$  is $u_{RMS(SO_{2} )}$ = $\sqrt{\frac{3R.273}{64} }$.

Suppose at T k temperature root mean square velocity of chlorine gas is $u_{RMS(cl) }$=$\sqrt{\frac{3RT}{71} }$.

Given that they are equal.

So,  $\sqrt{\frac{3R.273}{64} }$=$\sqrt{\frac{3RT}{71} }$.

⇒$\sqrt{\frac{273}{64} } =\sqrt{\frac{T}{71} }$.

⇒$\frac{273}{64}=\frac{T}{71}$.

⇒T=$\frac{273.71}{64}$=302.85 .

Hence, the temperature when the root mean square velocity of chlorine gas will be equal to $SO_{2}$ STP 302.85 k.

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