Question

At what temperature the root mean square velocity of chlorine gas will be equal that of So2 at N.T.P​

Answer 1

Step-by-step explanation:

At 327K

At 327K, the root mean square velocity of both the gases will be equal.

Answer 2

Answer:

At temperature 325K  the root mean square velocity of chlorine gas will be equal that of SO₂ at N.T.P.​

Step-by-step explanation:

We know that the root mean square velocity is given by:

$v_{rms}=\sqrt{\frac{3RT}{M} }$

Where T is the temperature

R is the gas constant

M is the molecular mass of the gas.

If the Root mean square velocity of chlorine gas is equal to root mean square velocity of SO₂.

The temperature of SO₂ at N.T.P., T₂ = 293K

The molecular mass of Cl₂ = 71g/mol

The molecular mass of SO₂ = 64g/mol

$\sqrt{\frac{3RT_1}{M_{Cl_2}} }=\sqrt{\frac{3RT_2}{M_{SO_2}} }$

$\frac{T_1}{M_{Cl_2}} =\frac{T_2}{M_{SO_2}}$

$T_1=\frac{(293)(71)}{(64)}$

T₁ = 325K

Therefore, the temperature of Chlorine gas is equal to 325K.

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