Physics, asked by TushanSaha, 4 months ago

at what temperature the volume of 28 gram into gas will be 2.56 ATM at pressure 10 litre​

Answers

Answered by akshaya2007d23
0

Answer:

The temperature at which 28g of N2 gas will occupy a volume of 10L at 2.46ATMis 299.63K.

Explanation:

Additional information:

It does not have any volume and it's mass is very negligible.

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Answered by Vespine
3

\large{ \underline{ \frak{ \orange{⌬⠀Given }}}}

▪︎ P = 2.46 atm

▪︎ V = 10 L

▪︎ n = 1 mole

Calculate the number of moles of N2 in 28 g N2 as follows

The mass of any substance present in one mole of it is equal to its molar mass.

Thus,

☆ 1 mol N2 = 28 g N2

Thus, the number of moles of N2 in 28 g N2 is 1 mol.

\large{ \underline{ \frak{ \blue{⌬⠀To \: Prove }}}}

▪︎ Temperature the volume of 28 g of N 2 gas of 2.56 atm pressure will be 10 L ??

\large{ \underline{ \frak{ \green{⌬⠀Formula }}}}

Calculate the temperature using the ideal gas equation as follows

The relationship between volume, temperature, pressure and the amount of gas is combined into the ideal gas law. The ideal gas is also known as the general gas equation. The temperature is directly proportional to the pressure and volume and inversely proportional to the amount of the gas.

We know the ideal gas equation is,

 \large\boxed{ \underline{ \mathbb{{ \red{PV=nRT}}}}}\:☆

Where

  • P is the pressure of the ideal gas,
  • V is the volume of the ideal gas,
  • n is the number of moles of ideal gas,
  • R is the universal gas constant having a constant value 0.082 litre atm/K mol
  • T is the temperature of the gas.

Rearrange the ideal gas equation for the temperature as follows:

:  \implies \:  \sf \: T= \dfrac{PV}{nR}

\large{ \underline{ \frak{ \pink{⌬⠀Solution }}}}

Substitute 2.46 atm for the pressure, 10 litre for the volume, 1 mol for the number of moles, 0.082 litre atm/K mol for the universal gas constant and calculate the value of temperature. Thus,

\sf{⟼T= \dfrac{2.46 atm×10 litre}{1 mol×0.082 litre atm/K mol}}

⟼\underline{ \sf{ \purple{T=300 K}}}

Thus, the temperature at which 28 g N2 occupies a volume of 10 litre at 2.46 atm is 300 K.

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